A contractor 2
A contractor has to complete his contract in 92 days. 234 men were set to do the work, each of them works for 16 hours/day. After 66 days, 4/7 of the work is completed. How many additional men may be employed, so that the work may be completed in time, each of additional men work 18h/day.
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Dr Math
contract period =92 days.
234 men work for 16 hours/day.
In 66 days they did 4/7 of the work .
addl men work 18h/day.
Work left 1-4/7=3/7
Days left 92-66=26
66 days 4/7 work
In 26 days will do 26*4/7*66=52/231
Work left = 3/7-52/231 =(99-52)/231=47/231
4/7 in 66*234*16 hours
1 work in 66*234*16*7/4 hours
47/231 work will do in 66*234*16*7/4*47/231 hours
= By 66*234*16*7/4*47/231/(26*18) men
=(66*234*16*7*47)/(4*231*26*18)= 188 men
234 men work for 16 hours/day.
In 66 days they did 4/7 of the work .
addl men work 18h/day.
Work left 1-4/7=3/7
Days left 92-66=26
66 days 4/7 work
In 26 days will do 26*4/7*66=52/231
Work left = 3/7-52/231 =(99-52)/231=47/231
4/7 in 66*234*16 hours
1 work in 66*234*16*7/4 hours
47/231 work will do in 66*234*16*7/4*47/231 hours
= By 66*234*16*7/4*47/231/(26*18) men
=(66*234*16*7*47)/(4*231*26*18)= 188 men
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