Tram

In the three-part tram went 206 passengers in front of others, 226 after others and in the middle half.

How many passengers went on the tram in total?

Correct answer:

x =  288

Step-by-step explanation:


a+b=206
b+c=226
b = 1/2·(a+b+c)
x=a+b+c

a+b = 206
b+c = 226
a-b+c = 0
a+b+c-x = 0

Row 3 - Row 1 → Row 3
a+b = 206
b+c = 226
-2b+c = -206
a+b+c-x = 0

Row 4 - Row 1 → Row 4
a+b = 206
b+c = 226
-2b+c = -206
c-x = -206

Pivot: Row 2 ↔ Row 3
a+b = 206
-2b+c = -206
b+c = 226
c-x = -206

Row 3 - 1/-2 · Row 2 → Row 3
a+b = 206
-2b+c = -206
1.5c = 123
c-x = -206

Row 4 - 1/1.5 · Row 3 → Row 4
a+b = 206
-2b+c = -206
1.5c = 123
-x = -288


x = -288/-1 = 288
c = 123/1.5 = 82
b = -206-c/-2 = -206-82/-2 = 144
a = 206-b = 206-144 = 62

a = 62
b = 144
c = 82
x = 288

Our linear equations calculator calculates it.

Try another example


Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
Do you have a system of equations and are looking for calculator system of linear equations?

You need to know the following knowledge to solve this word math problem:

Grade of the word problem:

Related math problems and questions: