Calculate 8262

The barrel of water weighed 64 kg. When We poured 28% of the water from it on the first day and a third of the rest on the second day, it weighed 38 kg. Calculate the empty barrel's weight and the water's initial weight.

Correct answer:

s =  14
v =  50

Step-by-step explanation:


s+v=64
s+(v - 0.28v - (v - 0.28v)/3) = 38

s+v=64
s+(v - 0.28·v - (v - 0.28·v)/3) = 38

s+v = 64
3s+1.44v = 114

Pivot: Row 1 ↔ Row 2
3s+1.44v = 114
s+v = 64

Row 2 - 1/3 · Row 1 → Row 2
3s+1.44v = 114
0.52v = 26


v = 26/0.52 = 50
s = 114-1.44v/3 = 114-1.44 · 50/3 = 14

s = 14
v = 50

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