Approximately 4222

The equator is approximately 40,000 km long. What would be the gap between an imaginary hoop 40001 km long and the ground? Would a mouse crawl under it?

Result

Yes

No

x =  159.15 m

Step-by-step explanation:

$x>10cm$

$$\begin{gathered} o_1=40000 \\ {o}_2=40001 \\ {r}_1=o_1/(2\pi )=40000/(2\cdot 3.1416)\doteq 6366.1977 \\ {r}_2=o_2/(2\pi )=40001/(2\cdot 3.1416)\doteq 6366.3569 \\ x=1000\cdot (r_2-r_1)=1000\cdot (6366.3569-6366.1977)=159.15\text{m} \end{gathered}$$

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