The manufacturer

The manufacturer found that 3% of the plates produced had a malfunction. Of the complaint, 75% are first and 25% second. What is the probability of producing first and second-class plates?

Correct answer:

p₁ =  72.75 %
p₂ =  24.25 %

Step-by-step explanation:

$$\begin{gathered} q=1-3/100=\frac{97}{100}=0.97 \\ {k}_1=75\%=\frac{75}{100}=\frac{3}{4}=0.75 \\ {k}_2=25\%=\frac{25}{100}=\frac{1}{4}=0.25 \\ {p}_1=100\cdot q\cdot k_1=100\cdot 0.97\cdot 0.75=72.75\% \end{gathered}$$

$p_2=100\cdot q\cdot k_2=100\cdot 0.97\cdot 0.25=24.25\%$

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