Train station

A man walks from his house to station. If he walks at 5 km/h he misses a train by 7 minutes. However, if he walks at 6 km/h, he reaches the station 5 minutes before the departure of the train. Find the distance covered by him to reach the station.

Correct answer:

x =  6 km

Step-by-step explanation:

t1=0:7=0 hr 7 min =0+607=0.1167 hr0.1167 v1=5 km/h t2=0:5=0 hr 5 min =0+605=0.0833 hr0.0833 v2=6 km/h  x=s1=s2 x = v1 (t+t1) x = v2 (tt2)  v1 (t+t1)=v2 (tt2) 5 (t+0.11666666666667)=6 (t0.083333333333333)  t=1.083333  t=11.08333333=1.08333333  t=12131.083333  x=v1 (t+t1)=5 (1.0833+0.1167)=6 km



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Showing 1 comment:
Dr. Math
The difference of the time between two speeds =12 minutes =1/5 hr,Therefore,
x/6-x/5=1/5
x/30=1/5
x=6 km where x is the distance from house to station.





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