Two cities

The distance between cities A and B is 132 km. At 9.00 AM, the cyclist started the bike at an average speed of 24 km/h, and at 10.00 AM, the B cyclist at an average speed of 30 km/h. How long and far from A will they both meet?

Correct answer:

t =  2 h
s₁ =  72 km

Step-by-step explanation:

$$\begin{gathered} v_1=24\text{km/h} \\ {v}_2=30\text{km/h} \\ s=132\text{km} \\ \Delta =10.00-9.00=1\text{h} \\ {v}_1\cdot (t+\Delta )+v_2\cdot t=s \\ 24\cdot (t+1)+30\cdot t=132 \\ 54t=108 \\ t=\frac{108}{54}=2 \\ t=2=2\text{h} \end{gathered}$$

$s_1=v_1\cdot (t+\Delta )=24\cdot (2+1)=72\text{km}$

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