Distance problem

A=(x, x)
B=(1,4)
Distance AB=√5, find x;

Correct answer:

x1 =  3
x2 =  2

Step-by-step explanation:

(x−1)2+(x−4)2=5  (x−1)2+(x−4)2=5  2x2−10x+12=0 2 ...  prime number 10=2⋅5 12=22⋅3 GCD(2,10,12)=2  x2−5x+6=0  a=1;b=−5;c=6 D=b2−4ac=52−4⋅1⋅6=1 D>0  x1,2​=2a−b±D​​=25±1​​ x1,2​=25±1​ x1,2​=2.5±0.5 x1​=3 x2​=2  x1​=3

Our quadratic equation calculator calculates it.

x2​=2

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