Distance problem 2

A=(x,2x)
B=(2x,1)
Distance AB=√2, find the value of x

Correct answer:

x1 =  1
x2 =  -0.2

Step-by-step explanation:

(x−2x)2 + (2x−1)2 = 2  (x−2x)2+(2x−1)2=2  5x2−4x−1=0  a=5;b=−4;c=−1 D=b2−4ac=42−4⋅5⋅(−1)=36 D>0  x1,2​=2a−b±D​​=104±36​​ x1,2​=104±6​ x1,2​=0.4±0.6 x1​=1 x2​=−0.2  x1​=1

Our quadratic equation calculator calculates it.

x2​=(−0.2)=−0.2

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