Temperature linear fit

At 2:00 a.m., the temperature was -7°F. At noon the temperature was 18°F. What expression represents the increase in temperature?

Correct answer:

e = 2.5*T-12

Step-by-step explanation:

t1​=−7 °F t2​=18 °F T1​=2 h T2​=12 h  e(T) = a⋅ T+b ?  t1​=a⋅ T1​+b t2​=a⋅ T2​+b (−7)=a⋅ 2+b 18=a⋅ 12+b  2a+b=−7 12a+b=18  Pivot:Row1↔Row2 12a+b=18 2a+b=−7  Row2−122​⋅ Row1→Row2 12a+b=18 0.83b=−10  b=0.83333333−10​=−12 a=1218−b​=1218+12​=2.5  a=25​=2.5 b=−12  e=2.5⋅ T−12

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Showing 1 comment:
Meldrin
On December 25,2009 the temperature at noon was approximated by T + 2 H = - 2° C.Estimate the temperature at 2 pm today?





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