The truncated

The truncated rotating cone has bases with radii r1 = 8 cm, r2 = 4 cm, and height v = 5 cm. What is the volume of the cone from which the truncated cone originated?

Correct answer:

V =  670.2064 cm3

Step-by-step explanation:

r1​=8 cm r2​=4 cm v=5 cm  r2​:x = r1​:(x+v)  r2​⋅ (x+v)=r1​⋅ x 4⋅ (x+5)=8⋅ x  4x=20  x=420​=5  x=5  h=v+x=5+5=10 cm  V=31​⋅ π⋅ r12​⋅ h=31​⋅ 3.1416⋅ 82⋅ 10=670.2064 cm3

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