Motorcycle 4373

A truck that is 6 m long travels at a speed of 66 km/h. A motorcycle traveling at a speed of 20 m/s overtakes him. Overtaking starts 16 m behind the car and ends 18 m in front of the car. How long does this overtaking last, and what track does the motorcycle cover?

Correct answer:

t =  24 s
s₂ =  480 m

Step-by-step explanation:

$$\begin{gathered} v_1=66\cdot 1000/3600=\frac{55}{3}\doteq 18.3333 \\ {v}_2=20 \\ s=6+16+18=40 \\ v=v_2-v_1=20-18.3333=\frac{5}{3}\doteq 1.6667 \\ t=s/v=40/1.6667=24\text{s} \end{gathered}$$

$s_2=v_2\cdot t=20\cdot 24=480\text{m}$

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