Statistical 36383

On the pages of the Czech Statistical Office, we can learn that in 1869, Prague and its suburbs had a total of 10,947 houses; in 1900, there were 18,838 houses. What was the annual percentage "increase" of houses in Prague between 1869 and 1900, assuming a constant percentage "increase"?

Correct answer:

p =  1.7664 %

Step-by-step explanation:

a=10947 b=18838 t=19001869=31  b = a   qt  b/a = qt  q=(b/a)1/t=3118838/109471.0177  q = 1 + p/100  p=100 (q1)=100 (1.01771)=1.7664%



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