Variations 3rd class

From how many elements can we create 13,800 variations of the 3rd class without repeating?

Correct answer:

n =  25

Step-by-step explanation:

V3(n) = (n3)!  n!  =  (n3)!  n(n1)(n2)(n3)!   = n(n1)(n2) = 13800 n(n1)(n2) = 13800 n  313800 = 23.986  22 < n  < 26  V(3,22) = 22   21   20 = 9240  V(3,23) = 23   22   21 = 10626  V(3,24) = 24   23   22 = 12144  V(3,25) = 25   24   23 = 13800  V(3,26) = 26   25   24 = 15600  n=25



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