The diagonal of rectangle problems - page 5 of 6
Number of problems found: 115
- TV diagonal
A diagonal TV is 0.56 m long. How big is the television screen if the aspect ratio is 16:9? - Rectangle In a rectangle with sides, 8 and 9 mark the diagonal. What is the probability that a randomly selected point within the rectangle is closer to the diagonal than any side of the rectangle?
- Quadrilateral 2
Show that the quadrilateral with vertices A(0,1), B(4,2), C(3,6) D(-5,4) has two right triangles. - Diagonal in rectangle
In the ABCD rectangle is the center of BC, point E, and point F is the center of the CD. Prove that the lines AE and AF divide diagonal BD into three equal parts.
- Construct 80719
Construct a rectangle ABCD if a = 8cm and the length of the diagonal AC is 13cm. Measure the length of the sides of the rectangle. - The intersection of the diagonals
In the rectangular coordinate system, a rectangle ABCD is drawn. These coordinates determine the vertices of the rectangle: A = (2.2) B = (8.2) C = (8.6) D = (2.6) Find the coordinates of the intersection of the diagonals of the ABCD rectangle. - Construct diagonals
The point B is a vertex of rectangle ABCD. The diagonal BD of this rectangle lies on the line p. Point X is an interior point of side AD of rectangle ABCD, and point Y is an internal point of side CD. Construct the missing vertices D, A, and C of the rect - Cardboard box
We want to make a cardboard box-shaped quadrangular prism with a rhombic base. The rhombus has a side of 5 cm and 8 cm, one diagonal long. The height of the box is 12 cm. The box will be open at the top. How many square centimeters do we need if we calcul - Box
The cardboard is a box-shaped quadrangular prism with a rhombic base. Rhombus has a side 5 cm, one diagonal 8 cm long, and the box's height is 12 cm. The package will open at the top. How many cm² of cardboard do we need to cover overlap and joints that a
- Faces diagonals
Find the cuboid volume if the cuboid's diagonals are x, y, and z (wall diagonals or three faces). Solve for x=1, y=1.1, z=1 - The glass
The glass has the shape of a cylinder with an inner diameter of 12 cm, and the height from the bottom is 16 cm. The cut skewer can be inserted diagonally into the glass so it does not protrude beyond the edge. What is the largest possible length of the cu - Prism - box
The prism's base is a rectangle with a side of 7.5 cm and 12.5 cm diagonal. The volume of the prism is V = 0.9 dm³. Calculate the surface of the prism. - Horizontally 8187
We turn the prism-shaped box with a height of 1 m and a square base with an edge of 0.6 m under a force of 350 N, which acts horizontally compared to the upper edge. What is the weight of the box? - Diagonals of a prism
The base of the square prism is a rectangle with dimensions of 3 dm and 4 dm. The height of the prism is 1 m. Find out the angle between the body diagonal and the base's diagonal.
- Calculate 74024
The diagonal of the axial section of the rotating cylinder is 6 cm, and its surface is 30 cm square. Calculate the radius of the base. - Calculate 70634
The axial section of the cylinder is a rectangle with a diagonal of u = 20 cm. The height of the cylinder is twice the diameter of the base. Calculate the cylinder volume in liters. - Calculate 4842
The area of the rotating cylinder shell is half the area of its surface. Calculate the surface of the cylinder if you know that the diagonal of the axial section is 5 cm. - Calculate 2548
Calculate the volume of a wooden box in the shape of a prism with the base of a rectangle if the box's width is 8 dm, the length is 14 dm, and the size of the body diagonal is 25 dm. - Axial section
The axial section of the cylinder is diagonal 45 cm long, and we know that the area of the side and the base area are in ratio 6:5. Calculate the height and radius of the cylinder base.
The angle between the body diagonal of a regular quadrilateral and its base is 60°. The edge of the base has a length of 10cm. Calculate the body volume.Do you have homework that you need help solving? Ask a question, and we will try to solve it. Solving math problems.
