Dilution

How many liters of water will have to be added to 1125 liters of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content?

Correct answer:

V1 =  562.5 l
V2 =  900 l

Step-by-step explanation:

V0=1125 l c1=45%=10045=209=0.45 c2=30%=10030=103=0.3 c3=25%=10025=41=0.25  V1  V  V2  c1 V0=c2 (V0+V1) 0.45 1125=0.3 (1125+V1)  0.3V1=168.75  V1=0.3168.75=562.5  V1=21125562.5=562.5 l
c1 V0=c3 (V0+V2) 0.45 1125=0.25 (1125+V2)  0.25V2=225  V2=0.25225=900  V2=900=900 l



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