Joshua

Joshua bought 7 1/2 kilograms of chicken. He used 2 3/4 kilograms for caldereta, 3 1/8 kilograms for tinola, and the rest for frying. How many kilograms of chicken did he use for frying?

Correct answer:

F =  1 ⁵⁄₈ = 13/8 kg

Step-by-step explanation:

$$\begin{gathered} T=7\frac{1}{2}=7+\frac{1}{2}=\frac{7\cdot 2+1}{2}=\frac{14+1}{2}=\frac{15}{2}=7.5\text{kg} \\ a=2\frac{3}{4}=2+\frac{3}{4}=\frac{2\cdot 4+3}{4}=\frac{8+3}{4}=\frac{11}{4}=2.75\text{kg} \\ b=3\frac{1}{8}=3+\frac{1}{8}=\frac{3\cdot 8+1}{8}=\frac{24+1}{8}=\frac{25}{8}=3.125\text{kg} \\ s=a+b=\frac{11}{4}+\frac{25}{8}=\frac{22}{8}+\frac{25}{8}=\frac{22+25}{8}=\frac{47}{8}=5.875\text{kg} \\ F=T-s=\frac{15}{2}-\frac{47}{8}=\frac{60}{8}-\frac{47}{8}=\frac{60-47}{8}=\frac{13}{8}=\frac{13}{8}\text{kg}=1\frac{5}{8}\text{kg}=1.625\text{kg} \end{gathered}$$

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