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Calculate how many g's (gravity accelerations) the glider pilot when turning the horizontal circles of radius 148 m flying at 95 km/h. Centripetal acceleration is proportional to the square of the speed and inversely proportional to the radius of rotation.

Consider a vertically acting gravity acceleration g=9.81 ms^-1.

Correct answer:

x =  1.11 g

Step-by-step explanation:

$$\begin{gathered} {a}_C=\frac{v^2}{r}=4.705m/s^2 \\ x=\frac{a}{g} \\ {a}^2=g^2+a_C^2 \\ x=\frac{\sqrt{g^2+a_C^2}}{g} \\ x=\frac{\sqrt{9.81^2+(\frac{26.389^2}{148}{)}^2}}{9.81} \\ x=1.11\text{g} \end{gathered}$$

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