Three-member 69274

The teacher wants to create one three-member team of four girls and four boys, with one girl and two boys. How many different options does it have to create a team?

Correct answer:

n =  24

Step-by-step explanation:

$$\begin{gathered} C_2(4)=\left(\genfrac{}{}{0ex}{}{4}{2}\right)=\frac{4!}{2!(4-2)!}=\frac{4\cdot 3}{2\cdot 1}=6 \\ n=4\cdot \left(\genfrac{}{}{0ex}{}{4}{2}\right)=4\cdot 6=24 \end{gathered}$$

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