Probability 64174

The banker deals, on average, with five clients a day. Find the probability that the number of clients (in one day) will be greater than 4.

Correct answer:

p =  0.1875

Step-by-step explanation:

$$\begin{gathered} m=5 \\ {p}_4=\left(\genfrac{}{}{0ex}{}{5}{4}\right)\cdot 0.5^4\cdot (1-0.5{)}^{5-4}=5\cdot 0.5^4\cdot 0.5^1\doteq 0.1563 \\ {p}_5=(\genfrac{}{}{0ex}{}{5}{5})\cdot 0.5^5\cdot (1-0.5{)}^{5-5}=1\cdot 0.5^5\cdot 0.5^0\doteq 0.0313 \\ p=p_4+p_5=0.1563+0.0313=0.1875 \end{gathered}$$

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