Gravitational 61894

The center of force on the wheel is 1.2 m from the axis of rotation, and the load is attracted by the earth's gravitational force equal to 800 newtons at a distance of 40 cm from the axis of rotation. How much force F2 does the worker lift the wheel?

Correct answer:

F₂ =  266.6667 N

Step-by-step explanation:

$$\begin{gathered} r_2=1.2\text{m} \\ {F}_1=800\text{N} \\ {r}_1=40\text{cm}\to \text{m}=40:100\text{m}=0.4\text{m} \\ {M}_1=M_2 \\ {F}_1{r}_1=F_2{r}_2 \\ {F}_2=F_1\cdot \frac{r_1}{r_2}=800\cdot \frac{0.4}{1.2}=\frac{800}{3}\text{N}=266.6667\text{N} \end{gathered}$$

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