Millimeters 6019

In an isosceles right triangle, the arms are 50 mm long, and the height at the base is 35.35 mm. Calculate the perimeter of this triangle in millimeters.

Correct answer:

o =  170.7107 mm

Step-by-step explanation:

$$\begin{gathered} r=50\text{mm} \\ c=\sqrt{r^2+r^2}=\sqrt{50^2+50^2}=50\sqrt{2}\text{mm}\doteq 70.7107\text{mm} \\ o=2\cdot r+c=2\cdot 50+70.7107=170.7107\text{mm} \end{gathered}$$

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