Peter's rectangle

Peter had a rectangle 2 cm wide and of unknown length. The line had a 2 cm rectangle whose length was equal to the perimeter of Peter's rectangle. When they put the rectangles together with their widths, they got a new rectangle with a circumference of 63 cm. Find the area of Peter's rectangle.

Final Answer:

S1 =  17 cm2

Step-by-step explanation:




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