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Find whole numbers between 155 and 232 that are divisible by 2, 5, and 10.

Correct answer:

x1 =  160
x2 =  170
x3 =  180
x4 =  190
x5 =  200
x6 =  210
x7 =  220
x8 =  230

Step-by-step explanation:

2 ...  prime number 5 ...  prime number 10=2⋅5 LCM(2,5,10)=2⋅5=10  d=LCM(2,5,10)=10 x1​=⌈155/d⌉⋅ d=⌈155/10⌉⋅ 10=160
x2​=x1​+d=160+10=170
x3​=x2​+d=170+10=180
x4​=x3​+d=180+10=190
x5​=x4​+d=190+10=200
x6​=x5​+d=200+10=210
x7​=x6​+d=210+10=220
x8​=x7​+d=220+10=230

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