Water tank

A 288 hectoliter of water was poured into the tank with dimensions of 12 m and, 6 m bottom, and 2 m depth. What part of the volume of the tank water is occupied? Calculate the surface of the tank wetted with water.

Correct answer:

p =  20 %
A =  86.4 m²

Step-by-step explanation:

$$\begin{gathered} a=12\text{m} \\ b=6\text{m} \\ c=2\text{m} \\ S=a\cdot b=12\cdot 6=72{\text{m}}^2 \\ V=S\cdot c=72\cdot 2=144{\text{m}}^3 \\ {V}_1=288/10=\frac{144}{5}=28.8{\text{m}}^3 \\ p=100\cdot V_1/V=100\cdot 28.8/144=20=20\% \\ {c}_1=V_1/S=28.8/72=\frac{2}{5}=0.4\text{m} \end{gathered}$$

$A=S+c_1\cdot (2\cdot a+2\cdot b)=72+0.4\cdot (2\cdot 12+2\cdot 6)=86.4{\text{m}}^2$

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