Two squares

Two squares with sides in the ratio 3:7 have a sum of their perimeters 58 cm. Calculate the sum of the area of these two squares.

Final Answer:

s =  121.945 cm2

Step-by-step explanation:

a1:a2=3:7 = o1:o2 o=58 cm  o = o1 + o2 = 4( a1 + a2 )  o = 4(a1+7/3 a1)  a1=4 (3+7)3 o=4 (3+7)3 58=2087=4.35 cm  a2=37 a1=37 4.35=20203=10.15 cm  S1=a12=4.352=4007569=18.9225 cm2 S2=a22=10.152=103.0225 cm2  s=S1+S2=18.9225+103.0225=121.945=121.945 cm2   Verifying Solution:  r=a1:a2=4.35:10.15=730.4286=3:7  o1=4 a1=4 4.35=587=17.4 cm o2=4 a2=4 10.15=5203=40.6 cm O=o1+o2=17.4+40.6=58 cm



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