Locomotive 40441

What is the pressure on the tracks when a 10-ton locomotive with eight wheels stands on it, and each wheel has a contact area of ​​4 cm²?

Correct answer:

p =  31250000 Pa

Step-by-step explanation:

$$\begin{gathered} m=10\text{t}\to \text{kg}=10\cdot 1000\text{kg}=10000\text{kg} \\ n=8 \\ {S}_1=4{\text{cm}}^2\to {\text{m}}^2=4:10000{\text{m}}^2=0.0004{\text{m}}^2 \\ g=10{\text{m/s}}^2 \\ S=n\cdot S_1=8\cdot 0.0004=\frac{2}{625}=0.0032{\text{m}}^2 \\ F=m\cdot g=10000\cdot 10=100000\text{N} \\ p=F/S=100000/0.0032=31250000\text{Pa} \end{gathered}$$

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