Hydraulic 36031

The hydraulic blade has pistons with an area of 10 cm² and 500 cm². How much force acts on the larger piston if we act on the smaller piston with a force of 100 N?

Correct answer:

F₂ =  5000 N

Step-by-step explanation:

$$\begin{gathered} S_1=10{\text{cm}}^2 \\ {S}_2=500{\text{cm}}^2 \\ {F}_1=100\text{N} \\ {p}_1=p_2 \\ {F}_1/S_1=F_2/S_2 \\ {F}_2=F_1\cdot \frac{S_2}{S_1}=100\cdot \frac{500}{10}=\frac{100\cdot 500}{10}=\frac{50000}{10}=5000\text{N} \end{gathered}$$

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