The tent

The tent shape of a regular quadrilateral pyramid has a base edge length of a = 2 m and a height of v = 1.8 m. If we have to add 7% of the seams, how many m² of cloth did we need to make the tent? How many m³ of air will be in the tent?

Correct answer:

S =  13.0931 m²
V =  2.4 m³

Step-by-step explanation:

$$\begin{gathered} a=2\text{m} \\ h=1.8\text{m} \\ s=\sqrt{h^2+(a/2{)}^2}=\sqrt{1.8^2+(2/2{)}^2}\doteq 2.0591\text{m} \\ {S}_1=a\cdot s/2=2\cdot 2.0591/2\doteq 2.0591{\text{m}}^2 \\ S=1.07\cdot (a^2+4\cdot S_1)=1.07\cdot (2^2+4\cdot 2.0591)=13.0931{\text{m}}^2 \end{gathered}$$

$V=a^2\cdot h/3=2^2\cdot 1.8/3=2.4{\text{m}}^3$

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