Cylindrical 3395

The cylindrical vase is 28 cm high. Its inner diameter d = 1.1 dm. How many liters of water will fit in it if the bottom thickness is 1.5 cm?

Correct answer:

V =  2.5184 l

Step-by-step explanation:

$$\begin{gathered} h_1=28\text{cm}\to \text{dm}=28:10\text{dm}=2.8\text{dm} \\ {h}_2=1.5\text{cm}\to \text{dm}=1.5:10\text{dm}=0.15\text{dm} \\ h=h_1-h_2=2.8-0.15=\frac{53}{20}=2.65\text{dm} \\ D=1.1\text{dm} \\ r=D/2=1.1/2=\frac{11}{20}=0.55\text{dm} \\ 1liter=1d{m}^3 \\ V=\pi \cdot r^2\cdot h=3.1416\cdot 0.55^2\cdot 2.65=2.5184\text{l} \end{gathered}$$

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