Individual 31411

On sources with voltage U = 12V, resistors R1 = 1 Ohm, R2 = 2 Ohm and R3 = 9 Ohm are connected in series. Determine the current I flowing from the source and the voltage drops U1, U2, and U3 on the individual resistors.

Correct answer:

I =  1 A
U₁ =  1 V
U₂ =  2 V
U₃ =  9 V

Step-by-step explanation:

$$\begin{gathered} U=12\text{V} \\ {R}_1=1\Omega \\ {R}_2=2\Omega \\ {R}_3=9\Omega \\ R=R_1+R_2+R_3=1+2+9=12\Omega \\ I=U/R=12/12=1\text{A} \end{gathered}$$

$U_1=I\cdot R_1=1\cdot 1=1\text{V}$

$U_2=I\cdot R_2=1\cdot 2=2\text{V}$

$U_3=I\cdot R_3=1\cdot 9=9\text{V}$

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