Solution 3092

How many liters of 80% alcohol need to be mixed with 4 liters of 40% alcohol to get 70% alcohol? How many liters of 70% solution do we get?

Correct answer:

x =  12 l
y =  16 l

Step-by-step explanation:

r1=80%=10080=54=0.8 r2=40%=10040=52=0.4 r3=70%=10070=107=0.7  V2=4 l  r1 x+r2 V2=r3 (x+V2) 0.8 x+0.4 4=0.7 (x+4)  0.1x=1.2  x=0.11.2=12  x=12=12 l
y=x+V2=12+4=16 l



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