Approximately 30131

Please calculate according to Pascal's law. Calculate the hydrostatic pressure at a depth of 300m below sea level if the density of seawater is approximately 1025kg per m³. At what depth below the surface is the hydrostatic pressure 4.5 MPa?

Correct answer:

p₁ =  3016.575 kPa
h₂ =  447.5274 m

Step-by-step explanation:

$$\begin{gathered} h=300\text{m} \\ g=9.81{\text{m/s}}^2 \\ \rho =1025{\text{kg/m}}^3 \\ p=\rho \cdot g\cdot h=1025\cdot 9.81\cdot 300=3016575\text{Pa} \\ {p}_1=p/1000=3016575/1000=3016.575\text{kPa} \end{gathered}$$

$$\begin{gathered} p_2=4.5\cdot 1000000=4500000\text{Pa} \\ {p}_2=\rho \cdot g\cdot h_2 \\ {h}_2=\frac{p_2}{\rho \cdot g}=\frac{4500000}{1025\cdot 9.81}=447.5274\text{m} \end{gathered}$$

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