Compressive 18853

The granite cube with an edge length of 1 dm and a weight of 2.5 kg is immersed in a container with water. How much buoyancy makes it lighter? How much compressive force does the cube exert on the bottom of the container?

Correct answer:

F =  10 N
F₂ =  15 N

Step-by-step explanation:

$$\begin{gathered} a=1\text{dm} \\ m=2.5\text{kg} \\ {m}_2=1\text{kg} \\ g=10{\text{m/s}}^2 \\ V=a^3=1^3=1{\text{dm}}^3 \\ w=1{\text{kg/dm}}^3 \\ {m}_2=w\cdot V=1\cdot 1=1\text{kg} \\ F=m_2\cdot g=1\cdot 10=10\text{N} \end{gathered}$$

$$\begin{gathered} F_1=m\cdot g=2.5\cdot 10=25\text{N} \\ {F}_2=F_1-F=25-10=15\text{N} \end{gathered}$$

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