Alcohol

6l 48% alcohol, how much must we add 52% alcohol to give 50% alcohol?

Correct answer:

x =  6 l

Step-by-step explanation:

V=6 l p1​=48%=10048​=2512​=0.48 p2​=52%=10052​=2513​=0.52 p=50%=10050​=21​=0.5  V⋅ p1​+x⋅ p2​=p⋅ (x+V) 6⋅ 0.48+x⋅ 0.52=0.5⋅ (x+6)  0.02x=0.12  x=0.020.12​=6  x=6=6 l

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