Cu ore

An ore contains 5% copper. How much ore is required to obtain 400 grams of copper?

Correct answer:

m1 =  8000 g

Step-by-step explanation:

r=5%=1005=201=0.05 m2=400 g  m1 r = m2  m1=m2/r=400/0.05=8000 g



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