When three

When three positive integers a, b, and c are multiplied together, their product is 64. Suppose a < b < c. In how many ways can the numbers be chosen?

Correct answer:

n =  3

Step-by-step explanation:

$$\begin{gathered} 64=2^6=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2 \\ 64=a\cdot b\cdot c \\ a<b<c \\ 1,2,32 \\ 1,4,16 \\ 2,4,8 \\ n=3 \end{gathered}$$

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