Treasures 82613

He divided his 15 gold treasures between his two sons in such a way that the elder got three parts and the younger got two parts of the entire wealth. How much treasure did each son get if all the parts were equal?

Correct answer:

a =  9
a =  6

Step-by-step explanation:

$$\begin{gathered} r_1=\frac{3}{3+2}=\frac{3}{5}=0.6 \\ a=r_1\cdot 15=\frac{3}{5}\cdot 15=\frac{3\cdot 15}{5}=\frac{45}{5}=9 \end{gathered}$$

$a=b=15-a=15-9=6$

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