Student examination

How many ways can a teacher select a group of 6 students to sit in the front row if the class has 13 students?

Correct answer:

n =  1716

Step-by-step explanation:

C6(13)=(613)=6!(136)!13!=6543211312111098=1716  n=(613)=1716



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Showing 2 comments:
Someone
the question doesnt say that the ordering doesnt matter, so wouldnt that mean the answer would be 13P6 or 1235520 ways?

1 year ago  2 Likes
Dr. Math
To determine the number of ways a teacher can select a group of 6 students from a class of 13 students, we will use the concept of combinations. Combinations are used when the order of selection does not matter.


Step 1: Understand the Problem
We need to select 6 students out of 13, and the order in which they are selected does not matter. This is a combination problem.


Step 2: Recall the Combination Formula
The number of ways to choose k items from n items is given by the combination formula:

C(n, k) = n!/k!(n - k)!,


where:
- n! (n factorial) is the product of all positive integers up to n ,
- k! is the factorial of k ,
- (n - k)! is the factorial of (n - k) .


Step 3: Substitute the Values
Here, n = 13 (total students) and k = 6 (students to select). Substitute these values into the formula:

C(13, 6) = 13!/6!(13 - 6)! = 13!/6! · 7!.



Step 4: Simplify the Factorials
We can simplify the factorials by canceling out common terms:

C(13, 6) = 13 × 12 × 11 × 10 × 9 × 8 × 7!/6! × 7!.


The 7! terms cancel out:

C(13, 6) = 13 × 12 × 11 × 10 × 9 × 8/6!.


Now, calculate 6! :

6! = 6 × 5 × 4 × 3 × 2 × 1 = 720.



Step 5: Calculate the Numerator
Calculate the numerator:

13 × 12 = 156,

156 × 11 = 1716,

1716 × 10 = 17160,

17160 × 9 = 154440,

154440 × 8 = 1235520.


So, the numerator is 1,235,520.


Step 6: Divide by the Denominator
Now, divide the numerator by the denominator:

C(13, 6) = 1,235,520/720 = 1,716.



Final Answer:
The number of ways to select a group of 6 students from 13 is:

1,716







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