Student examination
How many ways can a teacher select a group of 6 students to sit in the front row if the class has 13 students?
Correct answer:

Showing 2 comments:
Someone
the question doesnt say that the ordering doesnt matter, so wouldnt that mean the answer would be 13P6 or 1235520 ways?
1 year ago 2 Likes
Dr. Math
To determine the number of ways a teacher can select a group of 6 students from a class of 13 students, we will use the concept of combinations. Combinations are used when the order of selection does not matter.
Step 1: Understand the Problem
We need to select 6 students out of 13, and the order in which they are selected does not matter. This is a combination problem.
Step 2: Recall the Combination Formula
The number of ways to choose k items from n items is given by the combination formula:
where:
- n! (n factorial) is the product of all positive integers up to n ,
- k! is the factorial of k ,
- (n - k)! is the factorial of (n - k) .
Step 3: Substitute the Values
Here, n = 13 (total students) and k = 6 (students to select). Substitute these values into the formula:
Step 4: Simplify the Factorials
We can simplify the factorials by canceling out common terms:
The 7! terms cancel out:
Now, calculate 6! :
Step 5: Calculate the Numerator
Calculate the numerator:
So, the numerator is 1,235,520.
Step 6: Divide by the Denominator
Now, divide the numerator by the denominator:
Final Answer:
The number of ways to select a group of 6 students from 13 is:
Step 1: Understand the Problem
We need to select 6 students out of 13, and the order in which they are selected does not matter. This is a combination problem.
Step 2: Recall the Combination Formula
The number of ways to choose k items from n items is given by the combination formula:
C(n, k) = n!/k!(n - k)!,
where:
- n! (n factorial) is the product of all positive integers up to n ,
- k! is the factorial of k ,
- (n - k)! is the factorial of (n - k) .
Step 3: Substitute the Values
Here, n = 13 (total students) and k = 6 (students to select). Substitute these values into the formula:
C(13, 6) = 13!/6!(13 - 6)! = 13!/6! · 7!.
Step 4: Simplify the Factorials
We can simplify the factorials by canceling out common terms:
C(13, 6) = 13 × 12 × 11 × 10 × 9 × 8 × 7!/6! × 7!.
The 7! terms cancel out:
C(13, 6) = 13 × 12 × 11 × 10 × 9 × 8/6!.
Now, calculate 6! :
6! = 6 × 5 × 4 × 3 × 2 × 1 = 720.
Step 5: Calculate the Numerator
Calculate the numerator:
13 × 12 = 156,
156 × 11 = 1716,
1716 × 10 = 17160,
17160 × 9 = 154440,
154440 × 8 = 1235520.
So, the numerator is 1,235,520.
Step 6: Divide by the Denominator
Now, divide the numerator by the denominator:
C(13, 6) = 1,235,520/720 = 1,716.
Final Answer:
The number of ways to select a group of 6 students from 13 is:
1,716
Tips for related online calculators
Would you like to compute the count of combinations?
You need to know the following knowledge to solve this word math problem:
Related math problems and questions:
- Committee 35431
There are 24 students in the class. How many ways can we select a class committee? Where are the chairman, treasurer, and bulletin board?
- Seating rules
In a class, there are 24 seats, but in the 7.B class, there are only 18 students. How many ways can students sit? (The class has 12 benches. A bench is for a pair of students.) Result (large number) logarithm and thus write down as powers of 10.
- Students
Three students sit in the front row, and 11 students sit in every other row, more than in the previous row. Determine how many students are in the room when the room is nine lines and how many students are in the seventh row.
- Guests
How many ways can 8 guests sit down on 10 seats standing in a row?
- Friends in cinema
5 friends went to the cinema. How many possible ways can they sit in a row if one of them wants to sit in the middle and the remaining place does not matter?
- Desks
A class has 20 students. The classroom consists of 20 desks, with four desks in each of 5 different rows. Amy, Bob, Chloe, and David are all friends and would like to sit in the same row. How many possible seating arrangements exist, such as Amy, Bob, Chl
- School group
There are five girls and seven boys in the group. They sit in a row next to each other. How many options if no two girls sit next to each other?