Use L

Use L Hospital's rule to solve
(i) Lim x2+5x-14/x2-5x+6
X—>2
(ii)Lim x3+x2-x-1/x2-2x-3
X—>3

Correct answer:

a =  -9
b =  INF

Step-by-step explanation:

x1​=2 n1​=x12​+5⋅ x1​−14=22+5⋅ 2−14=0 d1​=x12​−5⋅ x1​+6=22−5⋅ 2+6=0   lim 0/0  ( x2+5x−14/x2−5x+6)′ = (2x+5) (x2−5⋅ x+6)′ = (2x−5)  a=2⋅ x1​−52⋅ x11​+5​=2⋅ 2−52⋅ 21+5​=−9
x2​=3 n2​=x23​+x22​−x2​−1=33+32−3−1=32 d2​=x22​−2⋅ x2​−3=32−2⋅ 3−3=0   lim 32/0  b=∞=INF

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