Ohms

Two resistors of 6 ohms and 8 ohms are connected in parallel to a flat battery U=4.5 V.

Calculate:
a) the total current,
b) the current in the branches.

Correct answer:

I =  1.3125 A
I₁ =  0.75 A
I₂ =  0.5625 A

Step-by-step explanation:

$$\begin{gathered} R_1=6\Omega \\ {R}_2=8\Omega \\ U=4.5\text{V} \\ {I}_1=U/R_1=4.5/6=\frac{3}{4}=0.75\text{A} \\ {I}_2=U/R_2=4.5/8=\frac{9}{16}=0.5625\text{A} \\ I=I_1+I_2=0.75+0.5625=1.3125\text{A} \end{gathered}$$

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