A math

A math teacher teaches Geometry and Precalculus. 37% of students take both math classes, and only 39% take just Geometry. What is the probability that a student will attend Precalculus given that they attended Geometry? What is the percentage of students that participated in Precalculus?

Correct answer:

P =  24 %
p₂ =  94.8718 %

Step-by-step explanation:

$$\begin{gathered} Precalculus: \\ GP=P(G\cap P) \\ GP=37\% \\ G=39\% \\ P=100-GP-G=100-37-39=24\% \end{gathered}$$

$$\begin{gathered} P(B|A)=P(A\cap B)/P(A) \\ P(P|G)=P(P\cap G)/P(G) \\ {p}_2=100\cdot \frac{GP}{G}=100\cdot \frac{37}{39}=\frac{100\cdot 37}{39}=\frac{3700}{39}=\frac{3700}{39}\%=94.8718\% \end{gathered}$$

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