Probability 86

At a business conference, there were ten social workers, 16 doctors, five lawyers, and two journalists.
If a person is picked at random from the entire group, what is the probability:
a) to be a lawyer
b) to be a doctor.

Correct answer:

p₁ =  15.1515 %
p₂ =  48.4848 %

Step-by-step explanation:

$$\begin{gathered} n=10+16+5+2=33 \\ {p}_1=100\cdot \frac{5}{n}=100\cdot \frac{5}{33}=\frac{100\cdot 5}{33}=\frac{500}{33}=\frac{500}{33}\%=15.1515\% \end{gathered}$$

$p_2=100\cdot \frac{16}{n}=100\cdot \frac{16}{33}=\frac{100\cdot 16}{33}=\frac{1600}{33}=\frac{1600}{33}\%=48.4848\%$

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