Assume

Assume that you are to buy 5 pesos worth of candy in two different stores. In your coin purse that contains two 20-peso coins, three 10-peso coins, six 5-peso coins, and seven 1-peso coins, what is the probability of getting two consecutive 5-peso coins from your purse, assuming that you already paid the first store a 5-peso coin before getting another 5-peso coin from your purse to pay the second store?

Correct answer:

p =  0.098

Step-by-step explanation:

$p=\frac{6}{2+3+6+7}\cdot \frac{6-1}{2+3+6+7-1}=\frac{5}{51}=0.098$

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