Probability 69714

The factory produces 35% of the tiles on line A, which produces scrap with a probability of 0.02, and 65% on line B, where the probability of scrap is 0.03. What is the probability that the selected tile will be defective?

Correct answer:

p =  2.65 %

Step-by-step explanation:

$$\begin{gathered} q_1=35\%=\frac{35}{100}=\frac{7}{20}=0.35 \\ {q}_2=1-q_1=1-0.35=\frac{13}{20}=0.65 \\ p=100\cdot (q_1\cdot 0.02+q_2\cdot 0.03)=100\cdot (0.35\cdot 0.02+0.65\cdot 0.03)=2.65\% \end{gathered}$$

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