Fuel efficiency

The gravimetric analysis of an anthracite fuel is 90% carbon, 3% hydrogen, 2% oxygen, and 1% nitrogen. Given that analysis of the dry combustion products by volume is 16.2% CO2, 3.5% O2, and 80.3% N2, during the combustion process of anthracite, which considers a solid fuel, some combustibles exit in fly ash with a weight fraction equal to 19% and temperature 270°C, The fly ash is 15 % of the total ash, and there are losses due to combustibles in slag ash where the combustibles with weight fraction equal 5% and temperature 4500°C. Ignoring the weight fraction of the water in the fuel, take the ambient condition 298K, 0.1MPa. Calculate the combustion efficiency if the weight fraction of ash in fuel is 30%. For anthracite fuel, take the value of the constant K in dry flue gas losses by 0.67 on the gross C.V basis and by 0.68 on the net C.V basis. The heat reaction of CO to that of CO2 equals 65.

Correct answer:

e =  0.7692

Step-by-step explanation:

$$\begin{gathered} P=1000\text{kJ} \\ Q=1300\text{kJ} \\ e=\frac{P}{Q}=\frac{1000}{1300}=0.7692 \end{gathered}$$

Try another example