Manganin

How long must a manganin wire with a diameter of 0.8 mm have a value of 10Ω?

Correct answer:

x =  10.472 m

Step-by-step explanation:

D=0.8 mm→ m=0.8:1000  m=0.0008 m R=10 Ω ρ=48⋅ 10−8≐4.8⋅10−7 Ω  r=D/2=0.0008/2=25001​=0.0004 m S=π⋅ r2=3.1416⋅ 0.00042≐5.0265⋅10−7 m2  R = ρ ⋅  x / S  x=S⋅ R/ρ=5.0265⋅10−7⋅ 10/4.8⋅10−7=10.472 m

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