Truncated cone

Calculate the volume of a truncated cone with base radiuses r1=19 cm, r2 = 11 cm, and height v = 5 cm.

Final Answer:

V =  1019.0541 cm3

Step-by-step explanation:

r1=19 cm r2=11 cm h=5 cm  q=r1r2r2=191111=811=1.375  h2=q h=1.375 5=855=6.875 cm  V1=31 π r12 h=31 3.1416 192 51890.1916 cm3  V2=31 π r22 h2=31 3.1416 112 6.875871.1375 cm3  V=V1V2=1890.1916871.1375=1019.0541 cm3



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solid geometryUnits of physical quantitiesGrade of the word problem

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