Algebra problem

This is algebra. Let n represent an unknown number.

1. Eight more than the number n
2. Three times the number n
3. The product of the numbers n and eight
4. Three less than the number n
5. The number n subtracted from three
6. Two less than three times the unknown

Final Answer:

a = 8+n
b = 3n
c = 8n
d = n-3
e = 3-n
f = 3n-2

Step-by-step explanation:

$a=8+n$

$b=3n$

$c=8n$

$d=n-3$

$e=3-n$

$f=3n-2$

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